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The Riesel problem

Show that 509203 is the smallest odd k with k·2^n − 1 composite for all n, by finding primes for the 41 remaining smaller k.

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README.md

The Riesel problem

In 1956 Hans Riesel showed that 509203⋅2n−1509203 \cdot 2^n - 1 is composite for every nn, because one of six small primes always divides it. Is 509203 the smallest odd number with this property? Settling the question means finding a prime of the form k⋅2n−1k \cdot 2^n - 1 for each of the 41 smaller values of kk still unresolved, and a distributed search is testing exponents beyond seventeen million.

Problem

An odd positive integer kk is a Riesel number if k⋅2n−1k \cdot 2^n - 1 is composite for every integer n≥1n \ge 1.

Conjecture. The smallest Riesel number is 509203509203. Equivalently, for every odd k<509203k < 509203 there is some n≥1n \ge 1 such that k⋅2n−1k \cdot 2^n - 1 is prime.

Background

Riesel (1956) proved that 509203509203 is a Riesel number: every number 509203⋅2n−1509203 \cdot 2^n - 1 is divisible by one of the primes in the covering set {3,5,7,13,17,241}\{3, 5, 7, 13, 17, 241\}, which works because the residues of 2n2^n modulo these primes repeat with a common period. The question mirrors the Sierpiński problem for numbers k⋅2n+1k \cdot 2^n + 1. Most known Riesel numbers come from covering sets, although Filaseta, Finch and Kozek (2008) gave one that is believed not to. The remaining candidates below 509203 are being tested by the volunteer computing project PrimeGrid.

What is known

  • 509203509203 is a Riesel number (Riesel, 1956), and no smaller kk is known to have a covering set.
  • PrimeGrid's statistics page, generated on 20 October 2026, lists 41 values of kk below 509203509203 for which no prime k⋅2n−1k \cdot 2^n - 1 is known; the smallest is k=23669k = 23669. Every remaining candidate has been tested up to nn of about 1.71×1071.71 \times 10^7.
  • Primes found during the search are very large; for example the table includes 107347⋅223427517−1107347 \cdot 2^{23427517} - 1, which eliminated k=107347k = 107347.

What would count as progress

  • A prime k⋅2n−1k \cdot 2^n - 1 for any of the 41 remaining values of kk. A claimed prime can be confirmed by an independent primality test, and each one reduces the problem.
  • A proof, for some remaining kk, that k⋅2n−1k \cdot 2^n - 1 is always composite, which would disprove the conjecture; this would most likely require a covering set or an algebraic factorisation.
  • Faster sieving and primality-testing software for numbers of this form, measured by the throughput of the search.
  • A formal proof of the Lean statement conjecture in OEIS/108129.lean, which encodes the problem through the OEIS sequence A108129.

References

  1. M. Filaseta, C. Finch and M. Kozek, On powers associated with Sierpiński numbers, Riesel numbers and Polignac's conjecture, J. Number Theory 128 (2008), 1916–1940.
  2. OEIS Foundation, A101036: Riesel numbers that have a covering set and A108129: the Riesel problem.
  3. PrimeGrid, The Riesel Problem statistics, retrieved 20 October 2026.

Source

Imported from Formal Conjectures OEIS/108129, curated by Google DeepMind and contributors. Open according to the source as of 2026-10-20. The statement above is written in our own words; see the source for the original wording, history and discussion.