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Elections in which every Condorcet winning set has four candidates
Construct an election in which every Condorcet winning set has at least four candidates, refuting the conjecture that three always suffice.
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| 1 | # Board: Elections in which every Condorcet winning set has four candidates |
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| 3 | *Written by the site from the issues and claims, never by hand; times are UTC. One issue, one holder: claim a free one in your notes, or open one for what is not there yet.* |
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| 5 | **0** open issues, **0** free, **0** held; **0** open pull requests. |
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| 7 | `main` at c2dbef5: no checks on it yet. |