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Hall's conjecture: a square extremely close to a cube

Find positive integers x, y with 0 < |y² − x³| < √x/100, beating the record ratio of about 46.6 in Hall's conjecture, unbroken since 1998.

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Hall's conjecture: a square extremely close to a cube

How close can a perfect square be to a perfect cube without being equal to it? Marshall Hall Jr. asked in 1971 how small ∣y2−x3∣|y^2 - x^3| can be, and conjectured that it is always at least a constant times x\sqrt{x}. The best example known, found by Noam Elkies, comes within x/46.6\sqrt{x}/46.6, and the task is to beat that ratio by a wide margin.

Problem

For positive integers x,yx, y with y2≠x3y^2 \ne x^3, define the Hall ratio

r(x,y)=x∣y2−x3∣.r(x, y) = \frac{\sqrt{x}}{\left| y^2 - x^3 \right|}.

Hall's original conjecture asserts that r(x,y)r(x, y) is bounded by an absolute constant.

Task. Find positive integers x,yx, y with y2≠x3y^2 \ne x^3 and r(x,y)>100r(x, y) > 100, that is, x>(100 ∣y2−x3∣)2x > \left(100\, \left| y^2 - x^3 \right|\right)^2.

Background

Hall raised the question in his 1971 paper "The Diophantine equation x3−y2=kx^3 - y^2 = k". The weaker form, ∣x3−y2∣>x1/2−o(1)\left| x^3 - y^2 \right| > x^{1/2 - o(1)}, is now recognised as a special case of the abc conjecture. Elkies calls the original strong form almost certainly false, but refuting it needs examples with ever larger ratios [2]. Elkies found an algorithm, based on lattice reduction, that finds all solutions of ∣x3−y2∣≪x1/2\left| x^3 - y^2 \right| \ll x^{1/2} with x<Nx < N in time O(N1/2+o(1))O(N^{1/2 + o(1)}). Running it up to N=1018N = 10^{18} produced ten new examples with ∣x3−y2∣<x\left| x^3 - y^2 \right| < \sqrt{x}, including one that broke the previous record ratio by a factor of nearly 10 [1, 2].

What is known

  • The record is r≈46.6r \approx 46.6, from x=5853886516781223x = 5853886516781223, y=447884928428402042307918y = 447884928428402042307918, x3−y2=1641843x^3 - y^2 = 1641843, found by Elkies [2]; Epoch dates it to 1998 and notes that it has not been improved since.
  • Elkies's page lists every solution of 0<∣x3−y2∣<x0 < \left| x^3 - y^2 \right| < \sqrt{x} with x<1018x < 10^{18}; the previous record ratio was 4.874.87 [2]. Later work developed new search algorithms [3].
  • formal-conjectures states the original conjecture in Lean as hall_conjecture in Hall.lean, together with Elkies' example.

What would count as progress

  • A pair (x,y)(x, y) with x>(100∣y2−x3∣)2x > \left(100 \left| y^2 - x^3 \right|\right)^2, of any size, checked exactly in integer arithmetic; this is the test Epoch's verifier applies.
  • Any pair with ratio above 46.6 would already be a new record; a method that produces many good pairs would shed light on how x3−y2x^3 - y^2 behaves.

References

  1. N. D. Elkies, Rational points near curves and small nonzero ∣x3−y2∣\left| x^3 - y^2 \right| via lattice reduction, ANTS-IV, Lecture Notes in Comput. Sci. 1838 (2000), 33–63. doi:10.1007/10722028_2 (arXiv:math/0005139)
  2. N. D. Elkies, List of integers x,yx, y with x<1018x < 10^{18} and 0<∣x3−y2∣<x1/20 < \left| x^3 - y^2 \right| < x^{1/2} (web page). people.math.harvard.edu/~elkies/hall.html
  3. I. Jiménez Calvo, J. Herranz and G. Sáez, A new algorithm to search for small nonzero ∣x3−y2∣\left| x^3 - y^2 \right| values, Math. Comp. 78 (2009), 2435–2444. doi:10.1090/S0025-5718-09-02240-6

Source

Imported from FrontierMath: Open Problems, hall-conjecture, curated by Epoch AI. Open according to the source as of 2026-10-20. The statement above is written in our own words; see the source for the original wording, history and discussion.